We were discussing the basics
of shear stress in turbulent flow, minor
head losses in pipe flow, hydraulic
gradient and total energy line, basic concept and working of
syphon, flow
through pipes in series, flow
through pipes in parallel and flow through branched pipes in the subject of
fluid mechanics, in our recent posts.

Now we will go ahead to see the concept of power
transmission through pipes, efficiency of power transmission and we will also
find here the condition for maximum transmission of power, in the subject of
fluid mechanics, with the help of this post.

###
**Power
transmission through pipes **

Power is transmitted through pipes by flowing water
or other liquids flowing through them. Power transmitted through pipes will be
dependent over the following factors as mentioned here.

- Weight of the liquid flowing through the pipe
- Total head available at the end of the pipe

Now we will consider a tank with which a pipe AB is
connected. Let us consider the following terms from figure.

L = Length of the pipe

D = Diameter of the pipe

H = Total head available at the inlet of the pipe

V= Velocity of flow in pipe

h

_{f}= Loss of head due to friction
f = Co-efficient of friction

Power transmitted at the outlet of the pipe will be
determined with the help of following formula as mentioned here.

###
**Efficiency
of power transmission **

Efficiency of power transmission will be determined
with the help of following formula as mentioned here.

###
**Condition
for maximum transmission of power **

Now we will find here the condition for maximum
transmission of power and it could be secured by differentiating the equation
of power transmitted at the outlet of the pipe.

Above expression is the condition of maximum
transmission of power. We can conclude from above equation that power
transmitted through a pipe will be maximum when the head loss due to friction
will be one-third of the total head at inlet.

###
**Maximum
efficiency of transmission of power **

As we have already secured the equation of
efficiency of power transmission through pipe and it is as mentioned here.

####
**η = (H- h**_{f}**)/H**

_{f}

Now we will use the value of h

_{f}in above equation to secure the maximum efficiency of transmission of power and we have following result as mentioned here.
η = (H- h

_{f})/H
η = (H- H/3)/H

####
**η = 66.7 %**

Further we will go ahead to find out the concept of flow through nozzles

**,**in the subject of fluid mechanics, with the help of our next post.
Do you have any suggestions? Please write in comment
box.

###
**Reference: **

Fluid mechanics, By R. K. Bansal

Image courtesy: Google

Please like and share

ReplyDeleteEngineers Classes for Competition(Regd) ECC-DELHI

ReplyDelete(Oldest JE/AE, AMIE & SEMESTER subject Technical Coaching)

Add:- C-70, Ground & 1st Floor, Mahavir Vihar, Dwarka sec-1, Near SEC-1 Bus Stop(HDFC ATM) & Police Post, New Delhi-45

M-9810366022, 9810366722

Nearest Metro-PALAM

www.engineersclasses4competition.com

Excellent article. Very interesting to read. I really love to read such a nice article. Thanks! keep rocking. cheap electrician

ReplyDeleteCompression fittings are not fool proof. If the pipe is not seated all the way onto the seat, the joint will leak, thus it is imperative that the end of the pipe be cut flat.fittings

ReplyDeleteThe next time I read a blog, I hope that it doesnt disappoint me as much as this one. I mean, I know it was my choice to read, but I actually thought you have something interesting to say. All I hear is a bunch of whining about something that you could fix if you werent too busy looking for attention. Wye Strainer

ReplyDeleteThe most straightforward ways property holders does to reline their channel lines would buy sealants, elastic sheets to envelop the line by or white concrete to cover holes and re-develop pipe harm. Be that as it may, this must be a brief arrangement and may cause greater obstacles in the line later on.pipe relining

ReplyDelete