We have seen shear stress distribution in rectangular section and shear stress distribution in circular section in our previous sessions. We were
discussing shear stress distribution in a beam of I section in our last post,
where we have seen that when we talk about shear
stress distribution for I section of beam, we will have to draw the shear
stress distribution in web and shear stress distribution in flange separately.

Before going ahead, I will request
you to please find the post “ Shear stress distribution in flange of I section”
for better understanding of current post which is based on the shear stress
distribution in web of I section.

Let us go ahead step by step for easy understanding,
however if there is any issue we can discuss it in comment box which is
provided below this post. So let us come to the main subject i.e. Shear stress
distribution in web of I section of a beam.

We have following information from above figure.

B = Overall width of I section of the beam

D = Overall depth of I section of the beam

b= Thickness of web of I section of the beam

d= Depth of web of I section of the beam

F = Shear force acting on the I section of the beam

N.A: Neutral axis of the beam section

EF: Layer of
the beam section at a distance y from the neutral axis of I section of the
beam.

A= Area of the section, where shear stress is to be determined

ȳ = Distance of C.G of the area, where
shear stress is to be determined, from neutral
axis of the beam section

###
*Shear stress at a section will be given by following formula
as mentioned here*

*Shear stress at a section will be given by following formula as mentioned here*

Where,

F = Shear force (N)

τ = Shear stress (N/mm

^{2})
A = Area of section, where shear stress is to be
determined (mm

^{2})
ȳ = Distance of C.G of the area, where
shear stress is to be determined, from neutral
axis of the beam section (m)

I = Moment of inertia of the given section about the neutral axis (mm

^{4})
b= Width of the given section where shear stress is to be determined (m)

A. ȳ = Moment of the whole shaded
area about the neutral axis

A

_{1}ȳ_{1}= Moment of shaded area of the flange about the neutral axis
A

_{2}ȳ_{2}= Moment of shaded area of the web about the neutral axis
We must have to note it here that when we need to
draw the shear stress distribution for web of I section, we will have to secure
the formula for the moment of the whole shaded
area about the neutral axis i.e. A. ȳ and it will be equal to the summation of
moment of shaded area of the flange about the neutral axis and moment of shaded
area of the web about the neutral axis of the beam section.

A. ȳ = A

_{1}ȳ_{1}+ A_{2}ȳ_{2}
Now we will first figure out the
value for A

_{1}ȳ_{1}i.e. Moment of shaded area of the flange about the neutral axis.
Similarly, let us find out the value for A

_{2}ȳ_{2}i.e. Moment of shaded area of the web about the neutral axis.
Let us find the moment
of the whole shaded area about the neutral axis i.e. A. ȳ

As we can see here from above
result that shear stress will vary with the value of y by following parabolic
law and we can also conclude here that value of shear stress will be reduced
with increase in the value of y.

Hence we can draw the shear stress distribution
diagram for I section beam. Before drawing the shear stress distribution
diagram for I section, we must have to secure the value of shear stress at y = d/2
and at y = 0.

*Shear stress at neutral axis, y = 0*

*Shear stress at neutral axis, y = d/2*
Shear stress distribution in I-section

We will
discuss bending stress of composite beam in our next post in the category of
strength of material. Please comment your feedback and suggestions in comment
box provided at the end of this post.

###
**Reference:**

Strength
of material, By R. K. Bansal

Image
Courtesy: Google

###
**Also
read**

Why 3d printing technology is not so
much succeeded?